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Question 62851This question is from textbook college algebra
: I need some help with this one...can anyone help me out? Thanks!
Directions: Let the function f be defined by y = f(x), where x and f(x) are real numbers. Find f(2), f(-3).
f(x) = 3/x^2+3
Thank you!
This question is from textbook college algebra
Answer by praseenakos@yahoo.com(507)   (Show Source):
You can put this solution on YOUR website! QUESTION:
Let the function f be defined by y = f(x), where x and f(x) are real numbers. Find f(2), f(-3).
f(x) = 3/x^2+3
ANSWER:
f(x) = 3/x^2+3
To find f(2), replace x by 2 in the given function.
f(2) = 3/2^2+3
=3/4 + 3
= 3/4 + 3/1 ( 3 can be written as 3/1)
= {4*3/4 + 4 * 3/1}/4
(Multiply the whole expression with the LCD of
the denominators and put the LCD as common denominator. 4 is the least common devisor of 1 and 4)
= {4*3/4 + 4 * 3/1}/4
= {1*3 + 12 }/4
= {15}/ 4
=15/4
Similarly,
f(-3) = 3/-3^2+3
= 3/9 + 3
= 1/3 + 3/1
= {3*1/3 + 3* 3/1}/3
= { 1 + 9 }/3
= 10/3
If your question is f(x) = 3/(x^2+3)
f(2) = 3/(2^2+3)
= 3 /(4 +3)
= 3/7
f(-3) = 3/(-3^2+3)
= 3 / ( 9 + 3)
= 3 / 12
= 1/4
Regards.
praseenakos@yahoo.co.in
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