SOLUTION: what is the domain of x^2+y^2=64

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Question 625376: what is the domain of x^2+y^2=64
Answer by reynard2007(52) About Me  (Show Source):
You can put this solution on YOUR website!

This is given:
x%5E2%2By%5E2=64
Let's rearrange to get: y%5E2=64-x%5E2
y=sqrt%2864-x%5E2%29


Remember that negative numbers do not have a square root. So, for sqrt%2864-x%5E2%29 to be existent 64-x%5E2 must be greater than or equal to zero:
64-x%5E2+%3E+0
x%5E2%3C64
x%3E-8 and x%3C8


So the domain of x is [-8,8]