SOLUTION: Question: Find the inverse of the given function - f(x) = 2x^3 - 3 This is what I've tried to do: f(x) = 2x^3 - 3 y = 2x^3 - 3 (turned it into a linear equation) x = 2y^3 - 3 (

Algebra ->  Functions -> SOLUTION: Question: Find the inverse of the given function - f(x) = 2x^3 - 3 This is what I've tried to do: f(x) = 2x^3 - 3 y = 2x^3 - 3 (turned it into a linear equation) x = 2y^3 - 3 (      Log On


   



Question 612653: Question: Find the inverse of the given function - f(x) = 2x^3 - 3
This is what I've tried to do:
f(x) = 2x^3 - 3
y = 2x^3 - 3 (turned it into a linear equation)
x = 2y^3 - 3 (switched x and y)
-2y^3 = -x -3 (isolate y)
-2y = ^3√-x - 3 (cube rooted both sides to get y on its own)
y = ^3√x + 3 / 2 (divided by - 2)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 2x^3 - 3
y = 2x^3 - 3 (turned it into a linear equation)
x = 2y^3 - 3 (switched x and y)
-2y^3 = -x -3 (isolate y)
--------
2y%5E3+=+x%2B3
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-2y = ^3√-x - 3 (cube rooted both sides to get y on its own)
y = ^3√x + 3 / 2 (divided by - 2) ***********
Divide by 2, not -2
y+=+root%283%2Cx%2B3%29%2F2
o/w it's correct