SOLUTION: Please help... Find the domain and range of the function F(t)= -t^2+4t+10

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Question 57438: Please help...
Find the domain and range of the function F(t)= -t^2+4t+10

Found 2 solutions by Nate, venugopalramana:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
parabola that opens downward
v(2,14)
Range: y+%3C=+14
Domain: all real values
graph%28300%2C300%2C-10%2C10%2C-6%2C15%2C-x%5E2%2B4x%2B10%29

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Please help...
Find the domain and range of the function F(t)= -t^2+4t+10
= -[T^2-4T-10]= -[T^2-2(T)(2)+2^2-2^2-10]= -[(T-2)^2-14]
F(T) = 14 -(T-2)^2
DOMAIN ..........THERE NO CONSTRAINTS..HENCE ALL REAL NUMBERS IS DOMAIN
RANGE ....MAXIMUM IS 14 SINCE (T-2)^2 IS ALWAYS POSITIVE AND WHEN SUBTRACTED
FROM WE GET 14 AS MAXIMUM VALUE
HENCE RANGE IS - INFINITY TO 14 ...THAT IS (- INFINITY,14]