SOLUTION: Determine algebraically whether this function is odd, even, both, or neither:
f(x) = (3[x]) / (1-x^2)
(the [x] is an absolute value)
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-> SOLUTION: Determine algebraically whether this function is odd, even, both, or neither:
f(x) = (3[x]) / (1-x^2)
(the [x] is an absolute value)
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Question 55709: Determine algebraically whether this function is odd, even, both, or neither:
f(x) = (3[x]) / (1-x^2)
(the [x] is an absolute value) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! f(x) = |3x| / (1-x^2)
f(-x)= |-3x| / (1-x^2)
-f(-x)= -|-3x| / (1-x^2)
Since f(x)= f(-x) the function is even
Comment: If you doubt this try some values of "x"
in f(x) and the same values in f(-x).
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Since f(x) does not equal -f(-x) the function is
not odd.
Cheers,
Stan H.
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