SOLUTION: (x)/(3)+(x)/(6)+(x)/(12)+(x)/(24)+?=5

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Question 541257: (x)/(3)+(x)/(6)+(x)/(12)+(x)/(24)+?=5
Found 2 solutions by ShortCircuit, KMST:
Answer by ShortCircuit(2) About Me  (Show Source):
You can put this solution on YOUR website!
In order to add fractions, you must find a common denominator. It is easiest to find the least common denominator. Because 3, 6, 12, and 24 all can be multiplied by certain numbers to equal 24, 24 is the least common denominator.
Starting with 3, it can be multiplied by 8 to get 24. x%2F3*8%2F8 will give you 8x%2F24. (You can do this because 8%2F8 equals 1 and anything times 1 still equals itself, so you aren't changing the value).
For 6, you know that 6*4=24. So x%2F6*4%2F4=4x%2F24
Then x%2F12*2%2F2=2%2F24.
Now that you have given each fraction a common denominator.
So your equation looks like:
8x%2F24+4x%2F24+2x%2F24+x%2F24=5
Now you can add the fractions together.
You get: 15x%2F24=5
Now you want to get x by itself, so you can multiply each side by 24: 24*15x%2F24=24*5
You will get: 15x=120
In order to get x by itself, all you have to do now is divide each side by 15: 15x%2F15=120%2F15
Your final result will be:
x=8
You can check your answer by plugging in 8 for each x. When you do that you will get 5=5, so you know that your answer is correct.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%29%2F%283%29%2B%28x%29%2F%286%29%2B%28x%29%2F%2812%29%2B%28x%29%2F%2824%29%2B...=5?
Infinite terms?
%28x%29%2F%283%29%2B%28x%29%2F%286%29%2B%28x%29%2F%2812%29%2B%28x%29%2F%2824%29%2B...=%28x%29%281%2F3%29(1+1/2+1/4+1/8+...)=%28x%29%281%2F3%29%282%29=2x%2F3
So if it was meant to involve the infinite series, that's the sum, and then
2x%2F3=5 --> x=15%2F2
Just the next term in the sequence? Then
%28x%29%2F%283%29%2B%28x%29%2F%286%29%2B%28x%29%2F%2812%29%2B%28x%29%2F%2824%29%2Bx%2F48=5 --> %28x%29%281%2F3%29%281%2B1%2F2%2B1%2F4%2B1%2F8%2B1%2F16%29=5 --> %28x%29%281%2F3%29%2831%2F16%29=5 --> 31x%2F48=5 --> x=240%2F31