SOLUTION: My problem is: (x+5)^2 + 4(x+5) - 32 I don't understand how to do this problem at all, but I did try. I somehow simplified it into this: x(x + 4 + 32/x) I asked my teacher if

Algebra ->  Functions -> SOLUTION: My problem is: (x+5)^2 + 4(x+5) - 32 I don't understand how to do this problem at all, but I did try. I somehow simplified it into this: x(x + 4 + 32/x) I asked my teacher if       Log On


   



Question 525668: My problem is: (x+5)^2 + 4(x+5) - 32
I don't understand how to do this problem at all, but I did try. I somehow simplified it into this:
x(x + 4 + 32/x)
I asked my teacher if I did it right and she said no, but didn't tell me the right answer or how to do it. I am in honors Algebra II and she says she shouldn't have to teach an honors student. So, I need help because I can't figure it out, and I don't even know what I am doing. Could you please help me?

Found 2 solutions by Maths68, solver91311:
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
=%28x%2B5%29%5E2%2B4%28x%2B5%29-32
=x%5E2%2B10x%2B25%2B4x%2B20-32
=x%5E2%2B10x%2B4x%2B25%2B20-32
=x%5E2%2B14x%2B45-32
=x%5E2%2B14x%2B13
=x%5E2%2B13x%2Bx%2B13
=x%28x%2B13%29%2B1%28x%2B13%29
=%28x%2B13%29%28x%2B1%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I would respond that since she is a teacher, and receives a salary for performing the duties of a teacher, that she has a fiduciary responsibility to teach you, your honors status notwithstanding. If she continues to refuse to help you, then I would go to the principal and ask that she be fired for nonfeasance and dereliction of her contractual duty. Of course, your story may just be whiny teenager bovine fecal matter presented for the purpose of trying to play on my sympathy. You see, I really don't believe your teacher said anything of the kind.

Be that as it may, there are a couple of ways to go about this depending on what you expect the final result to be. If you simply want a quadratic trinomial, then just expand the squared binomial, distribute the 4 across the other binomial, and collect like terms.

If you want a pair of binomial factors you can proceed as above and then factor the result -- a reasonably simple task for an honors Algebra II student. Or you can use the following little trick:

Let and then make the substitution:



Then factor



Replace the substitution





John

My calculator said it, I believe it, that settles it
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