SOLUTION: State the domain and range of f^-1 (x), given f(x)=(x-1)^2 +2 ** Please note their should be brackets around x-1 part** I'm not sure if the brackets will show up for you. This

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Question 51260: State the domain and range of f^-1 (x), given
f(x)=(x-1)^2 +2 ** Please note their should be brackets around x-1 part** I'm not sure if the brackets will show up for you.
This is what I have tried so far. I tried to find the inverse I am not sure if i am right.
f(x)= (x-1)^2+2
y=(x-1)^2+2
(y-1)^2=x-2
y-1= +/- Square root x-2
y= +/- square root x-2+1
f^-1 (x) = +/- square root x-2+1
Now I think I have to find the domain and range of this f^-1 (x) = +/- square root x-2+1. I am not sure how to do this. Can you please check my work and see if it is ok so far and help me find the domain and range and if I have made a mistake can you help me correct it. Thank-you so much.

Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website!
f(x) = (x - 1)^2 + 2
y = (x - 1)^2 + 2
x = (y - 1)^2 + 2
x - 2 = (y - 1)^2
+- = y - 1
+- + 1 = y
Domain: {x|}
Range: {y|all reals}