SOLUTION: Solve equation for y {{{ 2x^2+2y^2=5 }}}

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Question 483794: Solve equation for y
+2x%5E2%2B2y%5E2=5+
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
+2x%5E2%2B2y%5E2=5+
+2y%5E2=5-2x%5E2+
+2y%5E2%2F2=%285-2x%5E2%29%2F2+
y%5E2=%285-2x%5E2%29%2F2+
Use the principle of square roots:

y=%22%22+%2B-+sqrt%28%285-2x%5E2%29%2F2%29+

Rationalizing the denominator:

y=%22%22+%2B-+sqrt%28expr%28%285-2x%5E2%29%2F2%29%2Aexpr%282%2F2%29%29+


y=%22%22+%2B-+sqrt%28%282%285-2x%5E2%29%29%2F4%29+

y=%22%22+%2B-+sqrt%28%2810-4x%5E2%29%2F4%29+

y=%22%22+%2B-+sqrt%2810-4x%5E2%29%2F2+

Edwin