SOLUTION: The perimeter of a rectangle is 24 cm. Express the area of the rectangle in terms of the width x. P=2L+2w 24=2L+2x 24/2=L+X X=12/L

Algebra ->  Functions -> SOLUTION: The perimeter of a rectangle is 24 cm. Express the area of the rectangle in terms of the width x. P=2L+2w 24=2L+2x 24/2=L+X X=12/L       Log On


   

Question 469848: The perimeter of a rectangle is 24 cm. Express the area of the rectangle in terms of the width x.
P=2L+2w
24=2L+2x
24/2=L+X
X=12/L
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 24+cm. Express the area of the rectangle in terms of the width x. (do you mean the width W)

P=2L%2B2w
24cm=2L%2B2w
24cm%2F2=2L%2F2%2B2w%2F2
12cm=L%2Bw
w=12cm-L
the area is:
A=L%2Aw...substitute L
A=%2812cm-L%29%2AL
A=%2812cm%2AL%29-L%5E2

Let x and %2812-x%29 represent the width and length respectively

A+=+x%2812-x%29 or A=12x-x%5E2