SOLUTION: for the problem, f(x)=2x^3-15x^2+44x-39,i have to solve for f(x)=0 exactly,which i think is 1.5 but i can't fin the imaginary solutions.

Algebra ->  Functions -> SOLUTION: for the problem, f(x)=2x^3-15x^2+44x-39,i have to solve for f(x)=0 exactly,which i think is 1.5 but i can't fin the imaginary solutions.      Log On


   

Question 43521: for the problem, f(x)=2x^3-15x^2+44x-39,i have to solve for f(x)=0 exactly,which i think is 1.5 but i can't fin the imaginary solutions.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=2x%5E3-15x%5E2%2B44x-39
f%28x%29=%28x-1.5%29%282x%5E2+-+12x+%2B+26%29
a=2 b=-12 c=26
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%2812+%2B-+sqrt%28+%28-12%29%5E2-4%2A2%2A26+%29%29%2F%282%2A2%29+
x+=+%2812+%2B-+sqrt%28+144-208+%29%29%2F%284%29+
x+=+%2812+%2B-+sqrt%28+-64+%29%29%2F%284%29+
x+=+%2812+%2B-+8i%29%2F%284%29+
x+=+12%2F4+%2B-+8i%2F4+
x+=+3+%2B-+2i+
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+2x%5E3-15x%5E2%2B44x-39+%29+