SOLUTION: The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground

Algebra ->  Functions -> SOLUTION: The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground      Log On


   

Question 42742This question is from textbook
: The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft. This question is from textbook

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
h = -16t^2 + 112t
180 = -16t^2 + 112t
0 = -16t^2 + 112t - 180
0 = -4t^2 + 28t - 45
0 = -4(t - 2.5)(t - 4.5)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-4x%5E2+%2B+28x+-+45%29+