SOLUTION: What would be the vertex of the following: f(x)=x^2+10x+9
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Question 423688
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What would be the vertex of the following:
f(x)=x^2+10x+9
Answer by
Alan3354(69443)
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What would be the vertex of the following:
f(x)=x^2+10x+9
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The line of symmetry is x = -b/2a
x = -10/2 = -5
The vertex is (-5,f(-5))
= (-5,-16)