SOLUTION: I am having trouble with this problem, I need to sove for x. let h(x)= 4^(2x-1) h(x)=(square root of 2) sorry i'm not sure how to enter that.

Algebra ->  Functions -> SOLUTION: I am having trouble with this problem, I need to sove for x. let h(x)= 4^(2x-1) h(x)=(square root of 2) sorry i'm not sure how to enter that.       Log On


   

Question 32579This question is from textbook algebra for college students
: I am having trouble with this problem, I need to sove for x. let h(x)= 4^(2x-1)
h(x)=(square root of 2) sorry i'm not sure how to enter that. This question is from textbook algebra for college students

Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
Solution for x will be in terms of h(x).
h(x)= 4^(2x-1)
Take log on both sides
log h(x) = log [4^(2x-1)]
=> log h(x) = (2x-1) log 4
=> (2x-1) = [log h(x)]/[2 log 2] .... (log 4 = log 2^2 = 2 log 2)
=> 2x = 1 + [log h(x)]/[2 log 2]
=> x = (1/2)[1 + {log h(x)/(2 log 2)}]