SOLUTION: If g(x)=x^2+4x+2 find g(2) and g(x+2) so far I have g(2)= 2^2+4(2)+2 g(2)= 4+8+2 g(2)= 14 g(x+2)= (x+2)^2 + 4(x+2)+2 = x^2 + 4 + 4x + 8 + 2 = x^2 + 4x + 14

Algebra ->  Functions -> SOLUTION: If g(x)=x^2+4x+2 find g(2) and g(x+2) so far I have g(2)= 2^2+4(2)+2 g(2)= 4+8+2 g(2)= 14 g(x+2)= (x+2)^2 + 4(x+2)+2 = x^2 + 4 + 4x + 8 + 2 = x^2 + 4x + 14       Log On


   

Question 274913: If g(x)=x^2+4x+2 find g(2) and g(x+2)
so far I have
g(2)= 2^2+4(2)+2
g(2)= 4+8+2
g(2)= 14
g(x+2)= (x+2)^2 + 4(x+2)+2
= x^2 + 4 + 4x + 8 + 2
= x^2 + 4x + 14
I'm not sure if I should replace x with 2 or 14?
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
close but not exact
the g(2) is correct
1 mistake with the g(x+2)
g%28x%2B2%29=%28x%2B2%29%5E2%2B4%28x%2B2%29%2B2
expand (x+2)^2
g%28x%2B2%29=%28x%2B2%29%28x%2B2%29%2B4%28x%2B2%29%2B2
g%28x%2B2%29=%28x%5E2%2B4x%2B4%29%2B4%28x%2B2%29%2B2
g%28x%2B2%29=%28x%5E2%2B4x%2B4%29%2B%284x%2B8%29%2B2 add like terms
g%28x%2B2%29=x%5E2%2B8x%2B14