SOLUTION: The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where m is:

Algebra ->  Functions -> SOLUTION: The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where m is:       Log On


   



Question 184085: The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where
m is:
and b is:

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

The equation of the line that goes through the point ( 2, 5 ) is parallel to the line going through the points ( -1 ,2 ) and ( 1 ,6 ) is written in the form y = mx+b where
m is:
and b is:
Important:
We know when 2 lines are parallel, their Slope is the same:m%5B1%5D=m%5B2%5D
Solving for Slope, via Point-Slope Formsystem%28m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29%29
Thru points (-1,2) & (1,6):
m=%286-2%29%2F%281-%28-1%29%29=4%2F%281%2B1%29=4%2F2=2--->highlight%28m%5B1%5D=m%5B2%5D=2%29 REMEMBER.
Then Via Slope-Intercept Form: y=mx%2Bb on point (2,5):
5=2%282%29%2Bb
b=5-4=highlight%281%29, Y-Intercept
Then it follows eqn (thru point (2,5))-->y=2x%2B1
In doubt? We'll see the graph:

To see the line passing thru points (-1,2) & (1,6)
Slope-Intercept form, y=mx%2Bb
@ point (-1,2)
2=2%28-1%29%2Bb--->b=2%2B2=4
@ point (1,6)
6=2%281%29%2Bb--->b=6-2=4
It follows-------->y=2x%2B4
And we see the graph:

Thank you,
Jojo