SOLUTION: y = 1/2x^2 -2 x y 0 ? 1 ? 2 ? 3 ? Find y

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Question 182565: y = 1/2x^2 -2
x y
0 ?
1 ?
2 ?
3 ?
Find y
Found 2 solutions by checkley77, jojo14344:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
y = 1/2x^2 -2
y=0^2/2-2
y=-2
y=1^2/2-2
y=1/2-2
y=-3/2
y=2^2/2-2
y=4/2-2
y=2-2
y=0
y=3^2/2-2
y=9/2-2
y=4.5-2
y=2.5
x y
0 -2
1 -3/2
2 0
3 2.5

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Given: y=%281%2F2%29x%5E2-2
Remembersystem%28a=1%2F2%2Cb=0%2Cc=-2%29
Substituting value of "x"=0,1,2,3 to the eqn: y=%281%2F2%29x%5E2-2
y=%281%2F2%29%280%29%5E2-2=-2
y=%281%2F2%29%281%29%5E2-2=1%2F2-2=-1.5
y=%281%2F2%29%282%29%5E2-2=%281%2Fcross%282%29%29%28cross%284%292%29-2=0
y=%281%2F2%29%283%29%5E2-2=9%2F2-2=2.5
It follows:
x,y
0,-2
1,-1.5
2,0
3,2.5
We can solve for the vertex: x=-b%2F2a=-0%2F%282%281%2F2%29%29=0 X-Intercept
Substitute to the eqn:
y=%281%2F2%29%280%29%5E2-2=-2 Y-Intercept
Vertex--->(0,-2)

Thank you<
Jojo