SOLUTION: find the derivative.
1. x = ln(x+y+1)
and
2. F(x) = (square root of quantity 1 + x)- ln(1 + square root of quantity x + 1)
Algebra ->
Functions
-> SOLUTION: find the derivative.
1. x = ln(x+y+1)
and
2. F(x) = (square root of quantity 1 + x)- ln(1 + square root of quantity x + 1)
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Question 180834: find the derivative.
1. x = ln(x+y+1)
and
2. F(x) = (square root of quantity 1 + x)- ln(1 + square root of quantity x + 1) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the derivative.
1. x = ln(x+y+1)
1 = [1/(x+y+1)](1 + (y'))
y' = [x+y+1] -1
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and
2. F(x) = sqrt(1 + x)- ln[1 + sqrt(x + 1)]
F'(x) = (1/2)(1+x)^(-1/2) - [1/(1+sqrt(x+1)] * [(1/2)(x+1)^(-1/2)]
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Cheers,
Stan H.
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