SOLUTION: Thank you in advance for your help with this problem. f(x)=sqrt5x+1 I am looking for the domain. thanks again.

Algebra ->  Functions -> SOLUTION: Thank you in advance for your help with this problem. f(x)=sqrt5x+1 I am looking for the domain. thanks again.      Log On


   

Question 157430This question is from textbook college algebra
: Thank you in advance for your help with this problem. f(x)=sqrt5x+1 I am looking for the domain. thanks again. This question is from textbook college algebra

Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
if you assume that they don't allow imaginary numbers, then sqrt(x) cannot be negative.
this means x must be 0 or positive.
that would mean the domain is x>=0.
this is based on the assumption your original equation is y=sqrt%28x%29+%2B+1
if your original equation is y=sqrt%28x%2B1%29 then the domain would be different.
in that case, the domain would be x>=-1.