SOLUTION: approximate to the nearest tenth the negative real zeros of f(x)= x^3 - 2x^2 + 4

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Question 121412: approximate to the nearest tenth the negative real zeros of f(x)= x^3 - 2x^2 + 4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A quick graph shows the region of interest.
+graph%28+300%2C+300%2C+-5%2C+1%2C+-2%2C+2%2C+x%5E3-2x%5E2%2B4%29+
Plugging in negative values for x.
Look for y to change signs.
-2.0,-12
-1.9,-10.079
-1.8,-8.312
-1.7,-6.693
-1.6,-5.216
-1.5,-3.875
-1.4,-2.664
-1.3,-1.577
-1.2,-0.608
-1.1,0.249
There is a zero between x=-1.1 and x=-1.2.
highlight%28x=-1.1%29