SOLUTION: For the equations f(x) = (3)^x and g(x) = -(3)^2x+6-5, what are the transformations applied to f(x) to obtain g(x)?
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Question 1180811: For the equations f(x) = (3)^x and g(x) = -(3)^2x+6-5, what are the transformations applied to f(x) to obtain g(x)? Found 3 solutions by MathLover1, greenestamps, ikleyn:Answer by MathLover1(20849) (Show Source):
If you are working on a problem like this, your level of knowledge of math should be enough to know that proper use of parentheses is important. The function you show for g(x) is this:
It is obvious from the context of the problem that that is not the g(x) that you want. Surely you want this:
g(x) = -(3)^(2x+6)-5:
To determine the transformations, we need to rewrite the function so that the variable x has coefficient 1:
The transformations are in the order in which the expression would be evaluated for a given value of x.
Parent function: 3^x
(1) Inner parentheses: (x+3)
That shifts the graph 3 units left: 3^(x+3) (green)
(2) Outer parentheses: 2(x+3)
That compresses (dilates) the graph horizontally by a factor of 2, with the center of the dilation at x=-3: 3^(2(x+3)) (blue)
(3) Multiplication: multiply by -1
That flips the graph about the x-axis: -3^(2(x+3)) (purple)
(4) Addition/subtraction: subtract 5
That moves the graph down 5 units: -3^(2(x+3))-5 (yellow)
Summary....
The transformations, in order, are
shift left 3
compress horizontally by a factor of 2
flip vertically
shift down 5