|
Question 1180174: This question is from the CEMC math competition from last year.
The parabola y = -x^2 has vertex labelled P and intersects the x-axis at the points labelled A and B. The parabola translated from it's original position so that its vertex moves along the line y = x+4 to the point Q. In this new position, the parabola intersects the x-axis at the points labelled B and C. What are the coordinates of C?
Please view diagram here:
https://docs.google.com/document/d/1Cl3HrcoR6jibNzxfDTIilS3imSplLY8nQUU0OpU9vLA/edit?usp=sharing
Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
For the original parabola , the vertex is P( , ) and the x-intercepts are A( , ) and B( , ).
Let the vertex of the translated parabola be Q( , ).
Since the new parabola is a translation of the original, the equation of this new parabola is
Since Q lies on the line , we have and the equation of the newparabola is
Since B( , ) lies on the new parabola, we can substitute ( , ) into this equation:




Therefore, or .
The value corresponds to point P( , ) in theoriginal parabola. Therefore, and the vertex of the new parabola is Q( , ) and the equation of this parabola is
Since C is an -intercept of this parabola, to determine C set in the equation for the parabola and solve for :


= ± 
or ,
corresponds to point B, and the value corresponds topointC.
Therefore, the coordinates of C are ( , ).
|
|
|
| |