SOLUTION: For a certain company, the cost function for producing x items is C(x)=50x+200 and the revenue function for selling x items is R(x)=−0.5(x−120)2+7,200. The maximum capacity of
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Question 1178251: For a certain company, the cost function for producing x items is C(x)=50x+200 and the revenue function for selling x items is R(x)=−0.5(x−120)2+7,200. The maximum capacity of the company is 140 items.
Assuming that the company sells all that it produces, what is the profit function?
P(x)=
Preview Change entry mode .
Hint: Profit = Revenue - Cost as we examined in Discussion 3.
What is the domain of P(x)?
Hint: Does calculating P(x) make sense when x=−10 or x=1,000?
The company can choose to produce either 70 or 80 items. What is their profit for each case, and which level of production should they choose?
Profit when producing 70 items =
Number
Profit when producing 80 items =
Number
Can you explain, from our model, why the company makes less profit when producing 10 more units?
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For a certain company, the cost function for producing items is
and the revenue function for selling items is
The maximum capacity of the company is items.
Assuming that the company sells all that it produces, what is the profit function?
What is the domain of ?
Note that the company can sell at least items and at most items. Thus, the domain is
The company can choose to produce either or items. What is their profit for each case, and which level of production should they choose?
Profit when producing items =
so, if
Profit when producing items =
if
Can you explain, from our model, why the company makes less profit when producing 10 more units?
there is max number of units where square function (parabola) goes up, after that goes down
the maximum is when -expand
The maximum is: or units
=> for units the is and profit lower