SOLUTION: Find the cartesian eq'n of the following parametrics: {{{x=s^2+s}}}, {{{y=s^2-s}}} {{{s>0}}} I tried x-y and x+y but still s or s^2 left. Also I tried making s^2 subject and s su

Algebra ->  Functions -> SOLUTION: Find the cartesian eq'n of the following parametrics: {{{x=s^2+s}}}, {{{y=s^2-s}}} {{{s>0}}} I tried x-y and x+y but still s or s^2 left. Also I tried making s^2 subject and s su      Log On


   

Question 1154964: Find the cartesian eq'n of the following parametrics:
x=s%5E2%2Bs, y=s%5E2-s s%3E0
I tried x-y and x+y but still s or s^2 left. Also I tried making s^2 subject and s subject in each one and tried subbing in each other to cancel out the s's, so close but didn't work.
Last thing I tried was squaring both sides for each but could not get rid of the 2s%5E3
Please help, thank you very much.
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


Good start... and you're almost there.

But, at least in my experience, it takes a lot of practice to see where to go with this kind of problem to get where you want to end up.

Given:
x+=+s%5E2%2Bs
y+=+s%5E2-s

Look at x+y and x-y:
x%2By+=+2s%5E2
x-y+=+2s

From here you said you tried squaring both of those.

Try squaring only the second one....

I think you will see where to go after that to get an equation involving only x and y.