SOLUTION: Find the domain t(x)=(-3x+4x)÷(sqrt6x-6)

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Question 1146815: Find the domain t(x)=(-3x+4x)÷(sqrt6x-6)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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domain t(x)=(-3x+4x)÷(sqrt6x-6)
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t%28x%29=%28-3x%2B4x%29%2F%28sqrt%286x-6%29%29
If you intend some other function t, then express it with the grouping symbols in the correct places.

No restrictions on the numerator.

The denominator has the requirement 6x-6%3E0 or x-1%3E0 or x%3E1, since the denominator must not be zero.
Domain for t(x) in interval notation, (1, infinity).
highlight_green%28x%3E1%29



*********this part was wrong************************************
The denominator has the requirement 6x-6%3E=0 or x-1%3E=0 or x%3E=1.
The domain for t(x) is , using interval notation, [1, infinity).
x%3E=1
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Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.

The answer x >= 1 by @josgarithmetic is INCORRECT.



The correct answer is  x > 1.



At x = 1, the denominator of the function is 0 (zero, ZERO), so x=1 DOES NOT belong to the domain of the function.