SOLUTION: Hello. I did not find how to solve this problem in the Blitzer College Algebra Book. Here is the problem, which I have not been prepared to solve (no examples had been shown in the
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Question 1136338: Hello. I did not find how to solve this problem in the Blitzer College Algebra Book. Here is the problem, which I have not been prepared to solve (no examples had been shown in the book, very frustrating ad antipedagogical!)
Let f(x)= x^2 - x + 4 and g(x) = 3x - 5. Find g(1) and f(g(1)).
Please, show me the steps and if possible w/ explanations so that Imay understand how to solve this type of problems. Thanks Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! -------------simplify this; and then evaluate it for x=1. (That would be for the second part of your question. You can still find g(1) separately, again .)
You can put this solution on YOUR website!
Hello. I did not find how to solve this problem in the Blitzer College Algebra Book. Here is the problem, which I have not been prepared to solve (no examples had been shown in the book, very frustrating ad antipedagogical!)
Let f(x)= x^2 - x + 4 and g(x) = 3x - 5. Find g(1) and f(g(1)).
Please, show me the steps and if possible w/ explanations so that Imay understand how to solve this type of problems. Thanks
g(x) = 3x - 5
g(1) = 3(1) - 5 ------- Substituting 1 for x
g(1) = 3 - 5
g(1) = - 2
----- Substituting - 2 for g(1)
Tutor @MathTherary just explained you how to do it technically.
I only want to add to it the general approach description:
First step : You calculate g(1) by substituting x= 1 into the formula for g(x);
Second step : Then you calculate f(g(1)) by substituting the found value ( the number) g(1) into the given formula for f(x).
Both steps are extremely simple !
It may seem to be complicated, but when you do it one-two times, it becomes trivial !