SOLUTION: Find the tangent line equation for the function f(x)=(2x+1)(x^2-3) at the point x=0.

Algebra ->  Functions -> SOLUTION: Find the tangent line equation for the function f(x)=(2x+1)(x^2-3) at the point x=0.      Log On


   

Question 1123515: Find the tangent line equation for the function f(x)=(2x+1)(x^2-3) at the point x=0.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the tangent line equation for the function f(x)=(2x+1)(x^2-3) at the point x=0.
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f%28x%29=%282x%2B1%29%28x%5E2-3%29+=+2x%5E3+%2B+x%5E2+-+6x+-+3
f(0) = -3 --> the point (0,-3)
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f'(x) = 6x^2 + 2x - 6
f'(0) = -6
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m = -6 thru (0,-3)