Question 1086356: A set of 8 cards contains 1 joker. A and B are 2 players and A chooses 5 cards at random, B taking the
remaining 3 cards. What is the probability that A has the joker?
Found 2 solutions by Edwin McCravy, Fombitz:
Answer by Edwin McCravy(20056)   (Show Source):
You can put this solution on YOUR website!
If A has the joker, there are 7C4 ways he could have the other 4
non-jokers. So 7C4 is the numerator of the probability.
There are 8C5 ways he could have any 5 cards. So 8C5 is the denominator
of the probability.
Answer: 
Edwin
Answer by Fombitz(32388)  (Show Source):
You can put this solution on YOUR website! There are 56 possible combinations choosing 5 cards out of 8 total (A,B,C,D,E,F,G,J) where J is the joker.
There are 21 possible combinations choosing 5 cards out of 7 total.
(A,B,C,D,E,F,G) where there is no joker.
So in 21 of the 56 outcomes, the joker is in the B hand.
So in the A hand,
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