SOLUTION: Domain of f(x)=sqrt of x divided by x-3

[The answer above is incorrect.]

Domain of 

If three were no denominators or square roots containing x
the domain would be 



But this function has BOTH!

So we set what's under the square root greater than or equal to zero
and we set the denominator not equal to 0.

So we have  and 

Solving  we get 

Now we see that there is no need to require that , for
if x is greater than or equal 3, then it's automatically not equal 
to 0, so we only need to write the domain either in set builder
for as 

{x | x ≧ 3}

or in interval notation as



Edwin