SOLUTION: For {{{f(x) = 2/(x-3)}}} , solve for the domain and range in interval notation I found already the domain: (-infinity,3) u (3,+infinity) and i'm confident that it is correct

Algebra ->  Functions -> SOLUTION: For {{{f(x) = 2/(x-3)}}} , solve for the domain and range in interval notation I found already the domain: (-infinity,3) u (3,+infinity) and i'm confident that it is correct      Log On


   



Question 1041912: For f%28x%29+=+2%2F%28x-3%29 , solve for the domain and range in interval notation
I found already the domain:
(-infinity,3) u (3,+infinity)
and i'm confident that it is correct.
What confuses me is finding the Range.
I'm not confident on my answer:
(- infinity , 0] u [0, 3) u (3, + infinity)
can you give me the correct range in INTERVAL NOTATION and explain it efficiently? thanks.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Only one critical value for x, at x=3, where f is undefined.

The domain is the union, as you found.

RANGE:
What can be f, near but less than 3? What can be f, farther to the left of 3? What happens to f as x approaches 3 from the left?
Now ask and handle the same question but on the other side of x at 3.
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Also think what happens to f as x goes unbound to the left; and what happens as x goes unbound to the right.
-
You should be able to know what is the range of f, now.



graph%28400%2C400%2C-8%2C8%2C-8%2C8%2C2%2F%28x-3%29%29



All real numbers EXCLUDING 0.
Range is (-infinity,0) AND (0, infinity).


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(Range: I believe you have it (based on your personal message - not on what is in your posting here.)