Question 1032259: The function f(x)=x^2-10x+21 has a maximum value or a minimum value and determine the value. Found 2 solutions by adunbar, stanbon:Answer by adunbar(3) (Show Source):
You can put this solution on YOUR website! The function has f'(x) = 2x-10 = 0 at the maximum / minimum point.
That means, 2x = 10 so x = 5, hence, y = 5^2 - 10*5 + 21 = 25-50+21 = -4
The max / min is at (5, -4)
f''(x) = 2 > 0 Therefore is a minimum
You can put this solution on YOUR website! The function f(x)=x^2-10x+21 has a maximum value or a minimum value and determine the value.
-----
Since the coefficient of x^2 is positive, f(x) has a minimum value.
-------------
Min occurs when x = -b/(2a) = 10/(2) = 5
----
Max value = f(5) = 25 - 50 + 21 = -4
-------------------
--------------------
Cheers,
Stan H.
---------
(