SOLUTION: f(x) = (a/x) + (x^2/b) If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?

Algebra ->  Functions -> SOLUTION: f(x) = (a/x) + (x^2/b) If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?      Log On


   

Question 1021881: f(x) = (a/x) + (x^2/b)
If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%28b%2Fb%29%28a%2Fx%29%2B%28x%2Fx%29%28x%5E2%2Fb%29
%28ab%29%2F%28bx%29%2B%28x%5E3%29%2F%28bx%29
%28ab%2Bx%5E3%29%2F%28bx%29

The critical x values are at root%283%2C-ab%29 and at 0.