SOLUTION: f(x) = (a/x) + (x^2/b) If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?

Algebra ->  Functions -> SOLUTION: f(x) = (a/x) + (x^2/b) If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?      Log On


   



Question 1021869: f(x) = (a/x) + (x^2/b)
If a = 86 and b = 6, then what, to 2 decimal places, is the value of the x-coordinate of the critical point of f?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=86%2Fx%2Bx%5E2%2F6
df%2Fdx=-86%2Fx%5E2%2Bx%2F3=0
86%2Fx%5E2=x%2F3
x%5E3=258
Take the cube root of both sides for the solution.