SOLUTION: If g(x)=-x^2 determine the coordinates of the point of intersection of g(x) and its inverse algebraically where x<or equal to 0

Algebra ->  Functions -> SOLUTION: If g(x)=-x^2 determine the coordinates of the point of intersection of g(x) and its inverse algebraically where x<or equal to 0      Log On


   

Question 1021098: If g(x)=-x^2 determine the coordinates of the point of intersection of g(x) and its inverse algebraically where x
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x%5E2
To find the inverse interchange x and y and solve for the new y.
The new y is the inverse.
x=-y%5E2
y%5E2=-x
y=0+%2B-+sqrt%28-x%29
.
.
.
-x%5E2=-sqrt%28-x%29
x%5E2=sqrt%28-x%29
x%5E4=-x
x%5E4%2Bx=0
x%28x%5E3%2B1%29=0
x%28x%2B1%29%28x%5E2-x%2B1%29=0
Two solutions:
x=0 Not in the range we're interested in.
.
.
x%2B1=0
x=-1
.