SOLUTION: This is really a precalculas problem, I hope someone can help, I really need it. Thanks verify identity; cos[{{{pi}}}/2-x]/sin[{{{pi}}}/2-x]= tan x

Algebra ->  Finite-and-infinite-sets -> SOLUTION: This is really a precalculas problem, I hope someone can help, I really need it. Thanks verify identity; cos[{{{pi}}}/2-x]/sin[{{{pi}}}/2-x]= tan x      Log On


   

Question 63598: This is really a precalculas problem, I hope someone can help, I really need it.
Thanks
verify identity;
cos[pi/2-x]/sin[pi/2-x]= tan x
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
cos[pi/2-x]/sin[pi/2-x]
1/tan[pi/2-x]
1/tan^-1(x)
tan(x)