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Question 1119052: The population of a town is 10,000 people. The population is growing according to the function P(t) = 10,000(2^0.03t), where t is the number of years from the present and P is the population. What is the estimated population of the town after 3 years.
I can set the problem up but have a difficult time inputting in my calculator TI-84 plus
P(t) =10,000 (2^.03t)
P (3) = 10^4 (2^,03(3)
P (3) 10^4 (2^.09) after inputting this should give me the answer.

Click here to see answer by Theo(13342) About Me 
Question 1119052: The population of a town is 10,000 people. The population is growing according to the function P(t) = 10,000(2^0.03t), where t is the number of years from the present and P is the population. What is the estimated population of the town after 3 years.
I can set the problem up but have a difficult time inputting in my calculator TI-84 plus
P(t) =10,000 (2^.03t)
P (3) = 10^4 (2^,03(3)
P (3) 10^4 (2^.09) after inputting this should give me the answer.

Click here to see answer by greenestamps(13200) About Me 
Question 1119052: The population of a town is 10,000 people. The population is growing according to the function P(t) = 10,000(2^0.03t), where t is the number of years from the present and P is the population. What is the estimated population of the town after 3 years.
I can set the problem up but have a difficult time inputting in my calculator TI-84 plus
P(t) =10,000 (2^.03t)
P (3) = 10^4 (2^,03(3)
P (3) 10^4 (2^.09) after inputting this should give me the answer.

Click here to see answer by josgarithmetic(39617) About Me 
Question 1119052: The population of a town is 10,000 people. The population is growing according to the function P(t) = 10,000(2^0.03t), where t is the number of years from the present and P is the population. What is the estimated population of the town after 3 years.
I can set the problem up but have a difficult time inputting in my calculator TI-84 plus
P(t) =10,000 (2^.03t)
P (3) = 10^4 (2^,03(3)
P (3) 10^4 (2^.09) after inputting this should give me the answer.

Click here to see answer by MathTherapy(10552) About Me 

Question 1119059: A car rents for $40 per day plus 18 cents per mile. If x represents the number of miles Jorge drives per day, 40+0.18x represents the cost of the rental. If Jorge has $67 to spend for the daily car rental. What is the maximum number of miles he can travel per day
Click here to see answer by josgarithmetic(39617) About Me 

Question 1119109: If log (x+y)/2 = 1/2 (log x + log y) prove that x = y
Click here to see answer by ikleyn(52781) About Me 

Question 1119135: a population grows according to an exponential growth model, with P0 = 8 and P1 = 12
Click here to see answer by josgarithmetic(39617) About Me 

Question 1119139: Find the value of 1/√3-√2-1 correct upto three decimal places if√2= 1.414 ,√6=2.45
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Question 1119152: Hi, I have a problem that I don't understand how to solve, where there are two different interest rates. Can you help me with this?
"Madge invested $10,000 for one year, part at 8% annual interest and the rest at 12% annual interest. Her total interest for the year was $944. How much did she invest at each rate?"
Thank you!

Click here to see answer by ikleyn(52781) About Me 
Question 1119152: Hi, I have a problem that I don't understand how to solve, where there are two different interest rates. Can you help me with this?
"Madge invested $10,000 for one year, part at 8% annual interest and the rest at 12% annual interest. Her total interest for the year was $944. How much did she invest at each rate?"
Thank you!

Click here to see answer by greenestamps(13200) About Me 

Question 1119157: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3357 tickets overall. It has sold 157 more​ $20 tickets than​ $10 tickets. The total sales are ​$64 comma 64,640. How many tickets of each kind have been​ sold?
# $10 tickets sold
# $20 tickets sold
# $30 tickets sold

Click here to see answer by ankor@dixie-net.com(22740) About Me 
Question 1119157: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3357 tickets overall. It has sold 157 more​ $20 tickets than​ $10 tickets. The total sales are ​$64 comma 64,640. How many tickets of each kind have been​ sold?
# $10 tickets sold
# $20 tickets sold
# $30 tickets sold

Click here to see answer by ikleyn(52781) About Me 
Question 1119157: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3357 tickets overall. It has sold 157 more​ $20 tickets than​ $10 tickets. The total sales are ​$64 comma 64,640. How many tickets of each kind have been​ sold?
# $10 tickets sold
# $20 tickets sold
# $30 tickets sold

Click here to see answer by josgarithmetic(39617) About Me 

Question 1119075: The cost of hiring a catering service to serve food for a party is 150 pesos per head for 20 persons or less,130 pesos per head for 21 to 50 persons and
110 pesos per head for 51 to 100 persons.For 101 or more persons,the cost is at 100 pesos per head.Represent the total cost as a piecewise function of the number or attendances of the party.

Click here to see answer by Theo(13342) About Me 

Question 1119181: To save for​ retirement, Karla Harby put ​$550 each month into an ordinary annuity for 20 years. Interest was compounded monthly. At the end of the
20 ​years, the annuity was worth ​$226,173. What annual interest rate did she​ receive?
**(Answer has to be in "%", and "2" decimal places).

Click here to see answer by Theo(13342) About Me 

Question 1119192: Hi, I need some help with this interest problem, which I don't understand how to use a system of equations to solve it.
"Bruce invested in stock paying a 10.5% dividend. Maya invested $4,000 more than Bruce in a tax-free bonds paying 7½% annual simple interest. If they invested for one year and Maya’s income from the investment was $75 more than Bruce’s, find out how much each invested."
Thank you!

Click here to see answer by ankor@dixie-net.com(22740) About Me 

Question 1119204: I kind of get that when you are solving an inequality like ∣5x+1∣>3 that you are supposed to do it in two cases. But, what I don't get is why one of those cases is 5x+1<−3 because I thought that absolute values can never be negative. Why do we do that case?
Click here to see answer by addingup(3677) About Me 
Question 1119204: I kind of get that when you are solving an inequality like ∣5x+1∣>3 that you are supposed to do it in two cases. But, what I don't get is why one of those cases is 5x+1<−3 because I thought that absolute values can never be negative. Why do we do that case?
Click here to see answer by ikleyn(52781) About Me 
Question 1119204: I kind of get that when you are solving an inequality like ∣5x+1∣>3 that you are supposed to do it in two cases. But, what I don't get is why one of those cases is 5x+1<−3 because I thought that absolute values can never be negative. Why do we do that case?
Click here to see answer by MathTherapy(10552) About Me 

Question 1119240: I would like some help with this interest problem thank you!
"Jesse invested $2,000 more in stocks than in bonds. The bonds paid 7.2% interest and stocks paid 6%. The income from each investment was the same. How much interest did he receive in all."

Click here to see answer by josgarithmetic(39617) About Me 

Question 1119239: I am also stuck on this interest problem, I tried working it out with a system of equations which gave me a repeating decimal.
"Egbert invested $2,500 at 10% interest for one year. He has an additional $6,000 to deposit. At what rate must he invest the $6,000 to end the year with a total balance of exactly $9,440?"
Thank you!

Click here to see answer by josgarithmetic(39617) About Me 

Question 1119238: Please help me with this interest problem, I'm not sure what system of equations to write for it.
"Half of Roberta’s money is invested at 12% interest, one third of her money is at 11% and the remainder is invested at 9%. Her total annual income from the investments is 1,340. How much has Roberta invested altogether?"
Thank you!

Click here to see answer by ankor@dixie-net.com(22740) About Me 

Question 1119258: If x=-3 is a solution of the equation x^2=6x+do where d is a constant what is another value of x that satisfies the equation?
(Plz show step by step solution)
-5
-9
9
6

Click here to see answer by ikleyn(52781) About Me 

Question 1119257: If (2500)(8000)=20×10^x,then x=
4
5
6
None

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Question 1119256: For which of the following ordered pair (x,y)is x-3y <10 and x+y>7
(5,1)
(6,1)
(3,-3)
(4,4)

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Question 1119255: If x^2+x+y=8and x>0 then what is the value of y-8/x (x+1)
1
2
-1
None

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Question 1119259: If g (x)=7x-a where a is a constant and g(10)=3g(20) then g(30)=
-175
175
70
35

Click here to see answer by ikleyn(52781) About Me 

Question 1119203: A geometry teacher sent her students home with an assignment to analyze some lists of given side lengths—a,b, and c — to determine if each list of side lengths could form a triangle. And if a triangle was possible for any of the given lists, to draw a diagram of the triangle and label it with sides a, b, and c, and angles A, B, and C as shown below (side a opposite angle A, b opposite B, c and C opposite ).
Picture: https://api.agilixbuzz.com/Resz/~PW4LEAAAAAQsZBc1R9ciiB.CLm56DbZ6T1uAwIk1KSyJA/48780739,5F4,0,0/Assets/Media/Images/43.1-HOT2-Tris.jpg

The student was then asked to determine which angle was smallest and which was largest and to explain their reasoning. The teacher gave three lists to each student. Look at each student’s list,
Caroline got the following three lists:
List 1:
a = 6
b = 4
c = 5
List 2:
a = 10
b = 25
c = 13
List 3:
a = 6
b = 15
c = 17
Caroline’s answer looked like this:
Picture: https://api.agilixbuzz.com/Resz/~PW4LEAAAAAQsZBc1R9ciiB.CLm56DbZ6T1uAwIk1KSyJA/48780739,5F4,0,0/Assets/Media/Images/43.1-HOT2-Tris2.jpg
List 1: Angle A = largest; Angle C = smallest
The numbers in list 1 are all close enough that they can make a triangle. Angle A is the largest because it is across from the longest side, so the other two sides have to be spread wide enough to reach it. Angle C is the smallest because it is across from the smallest side so it can’t reach very far.
List 2: These numbers cannot make a triangle because 25 is too long and 10 & 13 can’t reach the ends of the 25 side.
List 3: Angle C = largest; Angle A = smallest
The lengths of this triangle are all close enough to make a triangle because 2 long sides can connect to a short side unlike List 2 where there were 2 short sides. Angle C is the largest because it is across from the longest side. Angle A is the smallest because it is across from the shortest side.
Graziella got the following three lists:
List 1:
a = 14
b = 2
c = 22
List 2:
a = 16
b = 5
c = 11
List 3:
a = 8
b = 9
c = 6
Graziella’s answer looked like this:
Picture: https://api.agilixbuzz.com/Resz/~PW4LEAAAAAQsZBc1R9ciiB.CLm56DbZ6T1uAwIk1KSyJA/48780739,5F4,0,0/Assets/Media/Images/43.1-HOT2-Tris3.jpg
List 1: No, c is too long 22. Side b is too short 2. It would not be a triangle.
List2: B has the smallest angle because b is the smallest side. A is the largest because a 16 is the longest side, so A has a wider angle.
List 3: This can be a triangle because of the length of each side. B has the largest angle because the opposite side b is longer, therefore, since is shorter, the angle should open more in order for b and c to touch. On the other hand, C has the smallest angle because c is shorter, therefore, C doesn’t open as wide as the other angles.
a. Critique the work of Graziella and Caroline. What did they do right? What did they do wrong?
b. What grade would you give Graziella and Caroline for this assignment? Why?
c. What clarifications can you add to their work to make their answers more worthy of a top grade?

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Question 1119312: Amits share was 2/9 of his grandfathers money,which he left behind and his sister Anjalis share was 1/7.If amits share was rs.54000 more than Anjalis share,find how much money their grandfather left behind?
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Question 1119323: a women has a total of $12,00 to invest. she invested part of the money in an account that pays 9% per year and the rest in an account that pays 10% per year. if the interest earned in the first year is $1160, how much did she invest in each account ? she invested $? at 9% and $? at 10%
Click here to see answer by ikleyn(52781) About Me 

Question 1119325: The cost C to produce x number of cd's is C= 50+5x. The Cd's are sold wholesales for $15 each, so revenue R is given by R=15x. Find how many cd's the manufacture needs to produce and sell to break even
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Question 1119335: If 2x+3y=12 and xy =6, find the value of 4x square +9y square .
P.S I am not able to put square up so I have written in words.Thanks.

Click here to see answer by ikleyn(52781) About Me 

Question 1119381: If Gina work Tuesday and Thursday for 6 hours. She works 12 hours per week and her pay check is $240.00. What is the hourly rate? (How much she gets paid per hour?)
Click here to see answer by ikleyn(52781) About Me 

Question 1119406: Need guidance please on the below question:
Given a line with equation 5x-2y=12. Write an equation in point-slope form of the line parallel to the given line through the point (4, -3).
Thank you!

Click here to see answer by Fombitz(32388) About Me 

Question 1119437: 1. Three CDs and 2 dvds cost £43 . 2 CDs and 3 DVD’s cost £47 . What is the cost of 1 cd
I have some 20p pieces. I have twice as many pieces as 20p pieces . I have twice as many 5p pieces as I have 10p pieces . I have £4.80 altogether. How many coins do I have ?

Click here to see answer by greenestamps(13200) About Me 
Question 1119437: 1. Three CDs and 2 dvds cost £43 . 2 CDs and 3 DVD’s cost £47 . What is the cost of 1 cd
I have some 20p pieces. I have twice as many pieces as 20p pieces . I have twice as many 5p pieces as I have 10p pieces . I have £4.80 altogether. How many coins do I have ?

Click here to see answer by josgarithmetic(39617) About Me 

Question 1119432: use inductive reasoning to predict the next number in the sequence
1,-1/2,1/4,-1/8,1/16

Click here to see answer by stanbon(75887) About Me 

Question 1119431: using the inductive reasoning to predict the next line in the pattern
(1x9)-6=3
(21x9)-6=183
(2*21x9)-6=2883
----
(3*21*9)-6 = 561
----------------------------
Cheers,
Stan H.
------------------

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Question 1119472: Determine whether the sets are equal, equivalent, both, or neither
{x| x is a whole number } and
{x| x is an integer}
A. Equal
B. Both
C.Neither
D.Equivalent

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Question 1119471: Find (A)for a set
A={x|x is a number on a clock face}

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Question 1119484: Determine the y-intercept of each of the following lines. Express your answer as a coordinate pair (x,y).
(a) The line passes through the points (0,7) and (3,0)
(b) The line given by the equation 3x-5y=15
(c) The line given by the equation y-4=3(x-9)
(d) The line that passes through the points (-2,-5) and (2,5)
(e) The line passing through the point (2,3) that is parallel to the line x+2y=-11

Click here to see answer by josgarithmetic(39617) About Me 

Question 1119509: Here's my problem. I'm asked to convert an equation from point slope form to slope intercept form.
The equation I came up with for point slope form is:
y-5= -2/3x(x-3)
Here's where I'm confused.
In slope intercept form I don't know which route to take, and I've done it both ways.
y-5= -2/3x+2/3(-3)
which produces: y= -2/3x+3
or
y-5=-2/3x+2/3(3)
which produces: y= -2/3x+7
The class shows an example where the point slope is, y-3=1/2(x-4), which results in a slope intercept conversion of y-3=1/2x-1/2(4)
This makes me believe that I should use
y-5= -2/3x+2/3(-3)
but then again, it could also be
y-5= -2/3x+2/3(3)
Help resolving this confusion wold be greatly appreciated.

Click here to see answer by josmiceli(19441) About Me 

Question 1119507: The numerator of a fraction is 7 less than the denominator.If one and one third is added to it,the fraction obtained is 14/9.Find the original fraction?
Click here to see answer by htmentor(1343) About Me 
Question 1119507: The numerator of a fraction is 7 less than the denominator.If one and one third is added to it,the fraction obtained is 14/9.Find the original fraction?
Click here to see answer by josmiceli(19441) About Me 

Question 1119523: Let A= (-6,7), B= (-4,11), and C= (-2,10) be three points in the xy-coordinate plane.
(a) Verify that the three points form a right triangle, and identify the point at the vertex where the right angle is. (use distance formula)
(b) Determine the midpoint of the hypotenuse of the right triangle.
(c) Find the equation of the line through the midpoint of the hypotenuse and the vertex opposite the hypotenuse (where the right angle is).

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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560