Tutors Answer Your Questions about Finance (FREE)
Question 1200292: The population of a town grows at a rate of e^1.2t-2t people per year (where t is the number of years). At t=2 years, the town has 1500 people. Approximately by how many people do the population grow between t=2 and t=5? What is the town’s population at t=5 year?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1200292: The population of a town grows at a rate of e^1.2t-2t people per year (where t is the number of years). At t=2 years, the town has 1500 people. Approximately by how many people do the population grow between t=2 and t=5? What is the town’s population at t=5 year?
Click here to see answer by ikleyn(52781)  |
Question 1200323: Evaluate the ceiling function for the given value.
g(x)=ceiling(x,0.25);x=7.63
The answer is 7.75. I’m confused as I thought for ceiling u have to round to the next INTEgER. But as per book answer is 7.75. I also don’t understand why there r 2 numbers , 7.63 and 0.25 . Will appreciate any kind of help . Thanks
Click here to see answer by ikleyn(52781)  |
Question 1200323: Evaluate the ceiling function for the given value.
g(x)=ceiling(x,0.25);x=7.63
The answer is 7.75. I’m confused as I thought for ceiling u have to round to the next INTEgER. But as per book answer is 7.75. I also don’t understand why there r 2 numbers , 7.63 and 0.25 . Will appreciate any kind of help . Thanks
Click here to see answer by math_tutor2020(3817) |
Question 1200323: Evaluate the ceiling function for the given value.
g(x)=ceiling(x,0.25);x=7.63
The answer is 7.75. I’m confused as I thought for ceiling u have to round to the next INTEgER. But as per book answer is 7.75. I also don’t understand why there r 2 numbers , 7.63 and 0.25 . Will appreciate any kind of help . Thanks
Click here to see answer by greenestamps(13200)  |
Question 1200361: In the year 2003, a company made $6.5 million in profit. For each consecutive year after that, their profit increased by 8%. How much would the company's profit be in the year 2007, to the nearest tenth of a million dollars?
Click here to see answer by ikleyn(52781)  |
Question 1200356: Jane has a pre-paid cell phone with Splint. She can't remember the exact costs, but her plan has a monthly fee and a charge for each minute of calling time. In June she used 130 minutes and the cost was $76.50. In July she used 510 minutes and the cost was $209.50.
A) Express the monthly cost as C as a function of X, the number of minutes of calling time she used.
Answer:
B) If Jane used 205 minutes of calling time in August, how much was her bill?
Answer: $
Click here to see answer by josgarithmetic(39617) |
Question 1200356: Jane has a pre-paid cell phone with Splint. She can't remember the exact costs, but her plan has a monthly fee and a charge for each minute of calling time. In June she used 130 minutes and the cost was $76.50. In July she used 510 minutes and the cost was $209.50.
A) Express the monthly cost as C as a function of X, the number of minutes of calling time she used.
Answer:
B) If Jane used 205 minutes of calling time in August, how much was her bill?
Answer: $
Click here to see answer by ikleyn(52781)  |
Question 1200798: you have $42,180.53 in a brokerage account, and you plan to deposit an additional $5,000 at the end of every future year until your account totals $250,000. you expect to earn 12% annually on the account. how many years will it take to reach your goal?
Click here to see answer by Theo(13342)  |
Question 1200831: Ryan, a consumer electronics salesperson, earns a base salary of $1600 per month and a commission of 7% on the amount of sales he makes. One month Ryan received a $2125 paycheck. Find the amount of his sales for the month.
Click here to see answer by ikleyn(52781)  |
Question 1200838: John has just purchased an apartment at a price of $5,000,000. He made a down-payment of
$2,000,000 and financed the remaining with a 30-year mortgage at APR 12%, compounded
monthly.
(a) Determine the size of the fixed month-end payments. (5 marks)
(b) Calculate the amount John still owes the bank right after the 120th payment was made.
(5 marks)
(c) Calculate the interest payment and the amount of principal paid in the 121st loan repayment.
(5 marks)
Click here to see answer by Theo(13342)  |
Question 1200851: Question photo link file:///C:/Users/chane/Downloads/mceclip0-1648477662552.webp
Part A: Estimate the cost of the equipment.
Cost = $
Part B: Estimate the salvage value of the equipment.
Salvage Value = $
Part C: Estimate the book value of the equipment in Year 4.
Book value in Year 4 = $
Part D: The equation for the book value of the farm equipment is
Value = 130,000 - 12,000(Years)
Use the equation to determine the book value when the equipment is six years old.
Book value at the end of Year 6 = $
Part E: Is your answer for Part D an example of interpolation or extrapolation?
Extrapolation
Interpolation
Part F: Which of the following is the correct interpretation of the "12,000" in this equation?
$12,000 is the annual depreciation of the equipment.
$12,000 is the total depreciation of the equipment.
$12,000 is the salvage value of the equipment.
$12,000 is the basis of the equipment.
Part G: The book value of the equipment will be $70,000 at the end of which year?
Click here to see answer by ikleyn(52781)  |
Question 1200852: Question Link File for this question. file:///C:/Users/chane/Downloads/mceclip0-1648477831833%20(1).webp
Part A: Estimate the basis (cost) of the rental property.
Basis = $
Part B: Estimate the book value of the property in Year 15.
Book value at Year 15 = $
Part C: Estimate the book value of the property in Year 25.
Book value at Year 25 = $
Part D: Is your answer from Part C an example of interpolation or extrapolation?
Interpolation
Extrapolation
Part E: Rental property does not have a salvage value; it depreciates to a value of zero. Estimate the class life used for this property.
Class life = how many years
Click here to see answer by ikleyn(52781)  |
Question 1200854: Question Link
file:///C:/Users/chane/Downloads/mceclip0-1648478439790%20(2).webp
The graph indicates the resale value of a certain style of Honda Accord LX
sedans. The value of a three-year old Honda LX Sedan 4D was $13,322. The value of an 11-year-old Honda LX Sedan 4D was $4,894. Assume that the depreciation of the vehicle between these years is linear. We want to find the value of a similar car that is eight years old.
Part A: Should the value of an eight-year-old Accord be closer to $13,322 or closer to $4,894?
Part B: You have multiple strategies for determining an estimate for the price of an eight-year-old Accord. Use one of the strategies and determine an estimate.
Estimated value = $
Click here to see answer by ikleyn(52781)  |
Question 1200859: Question Link Part A- Part D
https://ohm-website-data.s3.amazonaws.com/ufiles/1250064/mceclip1-1648477918709.png
Part A: The graph shows the number of RLB in Bexar County, Texas, for the years 2003-2007. However, the RLB for 2005 is missing. Use interpolation to estimate the number of RLB for Bexar County in that year.
Estimated RLB in 2005 =
Part B: The county planners found a linear trendline for the RLB data, where year represents the number of years since 2000 (for example, 2003 would be Year 3).
RLB = 639(year) + 22,869
Use this equation to find the predicted number of RLB in 2005.
Predicted RLB in 2005 =
Part C: The actual number of RLB in Bexar County in 2005 was 25,851. Find the percent error of the prediction in Part B. Round to the nearest whole percentage point. If your answer is negative, disregard the negative and enter only the percentage.
Percentage error = %
Question Link Part E- Part F
https://ohm-website-data.s3.amazonaws.com/ufiles/1250064/mceclip1-1648234934690.png
Part E: An economic downturn resulted in fewer births nationwide and in Bexar County. The actual number of RLB for Bexar County is shown in the following graph.
A trendline for the 2008-2011 data is given, where year represents the number of years since 2000 (for example, 2008 would be Year 8).
RLB = 31,816 - 552(year)
Use the trendline model to predict the number of RLB in 2015.
Predicted RLB in 2015 =
Part F: If this trend continues, in what year will the number of kindergarten students in Bexar County schools fall below 20,000? Recall that 93.5% of the RLB in any year attend kindergarten five years later.
Year =
Click here to see answer by ikleyn(52781)  |
Question 1200858: Question Link
https://ohm-website-data.s3.amazonaws.com/ufiles/1250064/mceclip0-1648477831833.png
Part A: Estimate the basis (cost) of the rental property.
Basis = $
Part B: Estimate the book value of the property in Year 15.
Book value at Year 15 = $
Part C: Estimate the book value of the property in Year 25.
Book value at Year 25 = $
Part D: Is your answer from Part C an example of interpolation or extrapolation?
Part E: Rental property does not have a salvage value; it depreciates to a value of zero. Estimate the class life used for this property.
Class life =
years
Click here to see answer by ikleyn(52781)  |
Question 1200857: Question Link
https://ohm-website-data.s3.amazonaws.com/ufiles/1250064/mceclip0-1648477662552.png
Part A: Estimate the cost of the equipment.
Cost = $
Part B: Estimate the salvage value of the equipment.
Salvage Value = $
Part C: Estimate the book value of the equipment in Year 4.
Book value in Year 4 = $
Part D: The equation for the book value of the farm equipment is
Value = 130,000 - 12,000(Years)
Use the equation to determine the book value when the equipment is six years old.
Book value at the end of Year 6 = $
Part E: Is your answer for Part D an example of interpolation or extrapolation?
Part F: Which of the following is the correct interpretation of the "12,000" in this equation?
$12,000 is the annual depreciation of the equipment.
$12,000 is the total depreciation of the equipment.
$12,000 is the salvage value of the equipment.
$12,000 is the basis of the equipment.
Part G: The book value of the equipment will be $70,000 at the end of Year.
Click here to see answer by ikleyn(52781)  |
Question 1200835: Question 1 (15 marks)
a) Asset X generates a perpetual stream of cash flows of $100,000 every 3 months. The relevant
interest rate is 12%, compounded quarterly. How much would you pay to buy Asset X today
if the first payment occurs right away? (5 marks)
b) You are considering depositing $1 million into a bank account. After one year, how much
more interest on interest will you find in Account (A) that provides an interest of 12%
compounded quarterly than Account (B) that provides an interest of 12% compounded semiannually?
(5 marks)
c) The Sharky Finance Ltd. has agreed to provide a loan to Meena on a “four-for-five” monthly
basis. That is, for every $4 Meena borrows today, she has to repay a total of $5 a month later.
What is the true yearly rate of this loan?
Click here to see answer by ikleyn(52781)  |
Question 1200837: a) Carter expects to live for 30 years more after his retirement. He would like to withdraw
$120,000 every year from his investment account (Account A) to pay for his living
expenses. Carter’s investment account (Account A) pays 5% interest per year.
How much money (a lump-sum) will Carter required to deposit in Account A at the beginning
of his retirement (at age 60) to pay for his living expenses if
(i) Account A start to pay interest one year after his retirement? (5 marks)
(ii) Account A start to pay interest on the day of his retirement? (5 marks)
[Hint: The total deposit that Carter made at the beginning of his retirement in Account A should
be the same as the amount required to provide for the monthly living expenses during his
retirement years.]
Continued with part (aii). Suppose Carter has just had his 35th birthday today and decided
to begin his retirement (exactly) 25 years from now, at his age of 60.
To ensure having sufficient funds to meet his goal, Carter plans to start depositing a fixed
amount at the end of every month to a retirement savings account (Account B) that pays
an interest of 12%, compounded monthly. The first deposit will be made today (on his 35th
birthday) and the last on his 58th birthday.
(i) Compute the size of the monthly deposit into Account B that will allow Carter to meet
the financial goal of his retirement. (8 marks)
(ii) If Carter is going to make one single (lump-sum) deposit into Account B on his 40th
birthday instead, how much will that be for him to achieve the goal? (2 marks)
Click here to see answer by ikleyn(52781)  |
Question 1200836: a) Carter expects to live for 30 years more after his retirement. He would like to withdraw
$120,000 every year from his investment account (Account A) to pay for his living
expenses. Carter’s investment account (Account A) pays 5% interest per year.
How much money (a lump-sum) will Carter required to deposit in Account A at the beginning
of his retirement (at age 60) to pay for his living expenses if
(i) Account A start to pay interest one year after his retirement? (5 marks)
(ii) Account A start to pay interest on the day of his retirement? (5 marks)
[Hint: The total deposit that Carter made at the beginning of his retirement in Account A should
be the same as the amount required to provide for the monthly living expenses during his
retirement years.]
Click here to see answer by ikleyn(52781)  |
Question 1200836: a) Carter expects to live for 30 years more after his retirement. He would like to withdraw
$120,000 every year from his investment account (Account A) to pay for his living
expenses. Carter’s investment account (Account A) pays 5% interest per year.
How much money (a lump-sum) will Carter required to deposit in Account A at the beginning
of his retirement (at age 60) to pay for his living expenses if
(i) Account A start to pay interest one year after his retirement? (5 marks)
(ii) Account A start to pay interest on the day of his retirement? (5 marks)
[Hint: The total deposit that Carter made at the beginning of his retirement in Account A should
be the same as the amount required to provide for the monthly living expenses during his
retirement years.]
Click here to see answer by Billy2002(1) |
Question 1200856: Question Link
https://ohm-website-data.s3.amazonaws.com/ufiles/1250064/mceclip0-1648478439790.png
The graph indicates the resale value of a certain style of Honda Accord LX sedans. The value of a three-year old Honda LX Sedan 4D was $13,322. The value of an 11-year-old Honda LX Sedan 4D was $4,894. Assume that the depreciation of the vehicle between these years is linear. We want to find the value of a similar car that is eight years old.
Part A: Should the value of an eight-year-old Accord be closer to $13,322 or closer to $4,894?
Part B: You have multiple strategies for determining an estimate for the price of an eight-year-old Accord. Use one of the strategies and determine an estimate.
Estimated value = $
Click here to see answer by ikleyn(52781)  |
Question 1200777: Ms. Ucalili wants to accumulate P20,000 by the end of 3
years to buy an iPod from her friend Mhutan. She has
P5,000 at present and would like to save equal, annual,
end-of-year deposits to pay for the iPod. How much
should she deposit at the end of each year in an account
paying an 8% interest to enable her to buy the iPod?
Click here to see answer by Theo(13342)  |
Question 1200874: Two people begin working on the same day for the same company. The starting salary of Person A is $52,000 and the starting salary of Person B is $43,000. Each person gets an annual raise of 3.5%.
Part A: How much money will Person A make in Year 5?
Person A's salary in Year 5 = $
Part B: How much money will Person B make in Year 5?
Person B's salary in Year 5 = $
Part C: How much more money will Person A make in the first five years (total) compared to Person B?
Answer: $
Click here to see answer by josgarithmetic(39617) |
Question 1200879: Two people begin working on the same day for the same company. The starting salary of Person A is $52,000 and the starting salary of Person B is $43,000. Each person gets an annual raise of 3.5%.
A: How much money will Person A make in Year 5?
A's salary in Year 5 = $
B: How much money will Person B make in Year 5?
Person B's salary in Year 5 = $
C: How much more money will Person A make in the first five years (total) compared to Person B?
Answer: $
Click here to see answer by josgarithmetic(39617) |
Question 1200902: The Flemings secured a bank loan of $352,000 to help finance the purchase of a house. The bank charges interest at a rate of 3%/year on the unpaid balance, and interest computations are made at the end of each month. The Flemings have agreed to repay the loan in equal monthly installments over 25 years. What should be the size of each repayment if the loan is to be amortized at the end of the term? (Round your answer to the nearest cent.)
Click here to see answer by Theo(13342)  |
Question 1200914: The price of a new car is $40,000. Assume that an individual makes a down payment of 25% toward the purchase of the car and secures financing for the balance at the rate of 7%/year compounded monthly. (Round your answers to the nearest cent.)
(a) What monthly payment will she be required to make if the car is financed over a period of 36 months? Over a period of 60 months?
36 months:
60 months:
(b) What will the interest charges be if she elects the 36-month plan? The 60-month plan?
36-month plan:
60-month plan :
Click here to see answer by Theo(13342)  |
Question 1200939: The Martinezes are planning to refinance their home. The outstanding balance on their original loan is $200,000. Their finance company has offered them two options. (Assume there are no additional finance charges. Round your answers to the nearest cent.)
Option A: A fixed-rate mortgage at an interest rate of 5.5%/year compounded monthly, payable over a 30-year period in 360 equal monthly installments.
Option B: A fixed-rate mortgage at an interest rate of 5.25%/year compounded monthly, payable over a 15-year period in 180 equal monthly installments.
(a) Find the monthly payment required to amortize each of these loans over the life of the loan.
option A:
option B:
(b) How much interest would the Martinezes save if they chose the 15-year mortgage instead of the 30-year mortgage?
Click here to see answer by Solver92311(821)  |
Question 1200937: What monthly payment is required to amortize a loan of $50,000 over 10 years if interest at the rate of 6%/year is charged on the unpaid balance and interest calculations are made at the end of each month? (Round your answer to the nearest cent.
Click here to see answer by Theo(13342)  |
Question 1200971: Carter expects to live for 30 years more after his retirement. He would like to withdraw $120,000 every year from his investment account (Account A) to pay for his living expenses. Carter’s investment account (Account A) pays 5% interest per year.
How much money (a lump-sum) will Carter required to deposit in Account A at the beginning of his retirement (at age 60) to pay for his living expenses if
(i) Account A start to pay $120,000 each year starting one year after his retirement? (5 marks)
(ii) Account A start to pay $120,000 each year startng on the day of his retirement? (5 marks)
Click here to see answer by Theo(13342)  |
Question 1200964: The Sharky Finance Ltd. has agreed to provide a loan to Meena on a “four-for-five” monthly basis. That is, for every $4 Meena borrows today, she has to repay a total of $5 a month later. What is the true yearly rate of this loan?
Click here to see answer by ikleyn(52781)  |
Question 1200962: The Ability-to-Repay Rule, adopted by the Consumer Financial Protection Bureau in compliance with the Dodd-Frank Wall Street Reform and Consumer Protection Act, requires lenders to determine whether a consumer applying for a Qualified Mortgage can afford to repay the loan. One of the requirements is that the borrower's total monthly debt (including property taxes) cannot exceed 43% of the borrower's monthly pre-tax income.† Suppose that the Foleys have applied for a $300,000 Qualified Mortgage with an interest rate of 5%/year compounded monthly and a term of 30 years. The property tax on the home they wish to purchase is $6000/year. If the Foleys' annual income is $72,000, will they qualify for the mortgage? (Round your answers to two decimal places.)
The Foley's monthly payment would be:
Their monthly income is:
Thus, provided they do not have other significant debts, the Foley's
Qualify / Do not qualify
for the mortgage.
Click here to see answer by Theo(13342)  |
Question 1200990: Asset X generates a perpetual stream of cash flows of $100,000 every 3 months. The relevant interest rate is 12%, compounded quarterly. How much would you pay to buy Asset X today if the first payment occurs right away? (5 marks)
Click here to see answer by Theo(13342)  |
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