SOLUTION: Find a function h(t) such that h'(t) = -32t + v[0] for all t, h(0) = 20 and h(1) = 0. (Here v[0] is a constant to be determined.)
Please explain how to solve
Thank you
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-> SOLUTION: Find a function h(t) such that h'(t) = -32t + v[0] for all t, h(0) = 20 and h(1) = 0. (Here v[0] is a constant to be determined.)
Please explain how to solve
Thank you
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Question 999310: Find a function h(t) such that h'(t) = -32t + v[0] for all t, h(0) = 20 and h(1) = 0. (Here v[0] is a constant to be determined.)
Please explain how to solve
Thank you Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find a function h(t) such that h'(t) = -32t + v[0] for all t, h(0) = 20 and h(1) = 0. (Here v[0] is a constant to be determined.)
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Integrate h'(t) to get:
h(t) = -16t^2 + v(0)t + C
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h(0) = -16*0^2+v(0)*0 + C = 20
So, C = 20
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h(1) = -16(1^2) + v(0)*1 + 20 = 0
-16 + v(0) + 20 = 0
v(0) = -4
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Ans: h(t) = -16t^2 -45 + 20
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Cheers,
Stan H.
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