SOLUTION: To two decimal places, find the value of k that will make the function f(x) continuous everywhere.
f of x equals the quantity 5 times x plus k for x less than or equal to negati
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-> SOLUTION: To two decimal places, find the value of k that will make the function f(x) continuous everywhere.
f of x equals the quantity 5 times x plus k for x less than or equal to negati
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Question 987753: To two decimal places, find the value of k that will make the function f(x) continuous everywhere.
f of x equals the quantity 5 times x plus k for x less than or equal to negative 5 and is equal to k times x squared minus 3 for x is greater than negative five
22.00
–0.92
–1.76
None of these Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! less than equal to -5, y=5x+k
greater than -5, y=kx^2-3
They need to be equal at -5
-25+k=25k-3
-22=24k
k=-22/24
k= -0.92
at -5, function is -25 5/6
at -5, function is (25*-(5/6)))-3
These are equal
