SOLUTION: How do I write the point-slope form of the line which passes through the point (-9,-3) and is parallel to the line {{{x/3 +2 = -3y}}}. Then write the general form of the equation.

Algebra ->  Finance -> SOLUTION: How do I write the point-slope form of the line which passes through the point (-9,-3) and is parallel to the line {{{x/3 +2 = -3y}}}. Then write the general form of the equation.       Log On


   

Question 984786: How do I write the point-slope form of the line which passes through the point (-9,-3) and is parallel to the line x%2F3+%2B2+=+-3y. Then write the general form of the equation.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x%2F3+%2B2+=+-3y,your given equation

y=-x%2F9-2%2F3, same equation in slope-intercept form.

A line parallel to it will have slope -1%2F9, which is same as the slope of the given line. This line parallel containing the given point, and in POINT-SLOPE form is y-%28-3%29=-%281%2F9%29%28x-%28-9%29%29.

You can do the rest. General Form takes a format Ax+By=C.