SOLUTION: normal distribution to approximate a binomial distribution.
2,881 adults were selected for a survey. if the probability, p, of a response to the survey is 71.85% what would be
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2,881 adults were selected for a survey. if the probability, p, of a response to the survey is 71.85% what would be
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Question 980356: normal distribution to approximate a binomial distribution.
2,881 adults were selected for a survey. if the probability, p, of a response to the survey is 71.85% what would be the probability that 2,086 or less adults would respond to the survey? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The point estimate is 0.72405
1 sample proportion test.
z=(0.72405-0.7186)/sqrt{ (.7185)(.2815)/2881}
standard error is 0.00837
The numerator is 0.005454
The quotient is z=+0.651
Probability of anything being less than z=0.6516 in a normal distribution is 0.743.
