SOLUTION: Find all solutions of each equation on the interval (0,2pi) Sin2 x = cos x (hint : sin(2x) = sin ( x + x))

Algebra ->  Finance -> SOLUTION: Find all solutions of each equation on the interval (0,2pi) Sin2 x = cos x (hint : sin(2x) = sin ( x + x))      Log On


   

Question 971379: Find all solutions of each equation on the interval (0,2pi)
Sin2 x = cos x (hint : sin(2x) = sin ( x + x))
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all solutions of each equation on the interval (0,2pi)
Sin2 x = cos x
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sin(2x)=cosx
sin(2x)-cosx=0
2sinxcosx-cosx=0
cosx(2sinx-1)=0
cosx=0
x=π/2, 3π/2
or
2sinx-1=0
sinx=1/2
x=π/6, 5π/6