SOLUTION: 5. Factor completely: w^2+5w-24 (w+12)(w-2) (w+6)(w-4) (w-8)(w+3) (w+8)(w-3)

Algebra ->  Finance -> SOLUTION: 5. Factor completely: w^2+5w-24 (w+12)(w-2) (w+6)(w-4) (w-8)(w+3) (w+8)(w-3)       Log On


   

Question 956976: 5. Factor completely: w^2+5w-24
(w+12)(w-2)
(w+6)(w-4)
(w-8)(w+3)
(w+8)(w-3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!

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Find a pair of factors of 24 that differ by 5.