SOLUTION: Which is the factored form of x^3 + 6x^2 – 25x + 18 = 0? A.(x + 1)(x – 3)(x – 6) = 0 B.(x + 1)(x – 2)(x + 9) = 0 C. (x – 1)(x – 3)(x – 6) = 0 D. (x – 1)(x – 2)(x + 9) =

Algebra ->  Finance -> SOLUTION: Which is the factored form of x^3 + 6x^2 – 25x + 18 = 0? A.(x + 1)(x – 3)(x – 6) = 0 B.(x + 1)(x – 2)(x + 9) = 0 C. (x – 1)(x – 3)(x – 6) = 0 D. (x – 1)(x – 2)(x + 9) =       Log On


   

Question 934536: Which is the factored form of x^3 + 6x^2 – 25x + 18 = 0?
A.(x + 1)(x – 3)(x – 6) = 0
B.(x + 1)(x – 2)(x + 9) = 0
C. (x – 1)(x – 3)(x – 6) = 0
D. (x – 1)(x – 2)(x + 9) = 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The product of the constant terms is 18.
A.%281%29%28-3%29%28-6%29=18 possible choice
B.%281%29%28-2%29%289%29=-18 not a possible choice
C.%28-1%29%28-3%29%28-6%29=-18 not a possible choice
D.%28-1%29%28-2%29%289%29=18 possible choice
.
.
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A and D remain as possible choices.
From D, x=1 would be a zero.
Checking the original polynomial,
1%5E3%2B6%281%29%5E2-25%281%29%2B18=0
1%2B6-25%2B18=0
25-25=0
0=0
True, so D is the correct factored form.