SOLUTION: hello..can someone help me ? I am establishing this trig identity Cosa^3+sinb^3/cosb+sinb= 2-sin2b/2 and I get to 1-cosbsinb. How can 1-cosbsinb = 2-sin2b/2 I am challenged by

Algebra ->  Finance -> SOLUTION: hello..can someone help me ? I am establishing this trig identity Cosa^3+sinb^3/cosb+sinb= 2-sin2b/2 and I get to 1-cosbsinb. How can 1-cosbsinb = 2-sin2b/2 I am challenged by       Log On


   

Question 927644: hello..can someone help me ? I am establishing this trig identity
Cosa^3+sinb^3/cosb+sinb= 2-sin2b/2 and I get to 1-cosbsinb. How can 1-cosbsinb = 2-sin2b/2 I am challenged by this because I do not see an identity that relates. Thank you in advance !!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint:

sin%282x%29+=+2%2Asin%28x%29%2Acos%28x%29


sin%282x%29%2F2+=+sin%28x%29%2Acos%28x%29


sin%28x%29%2Acos%28x%29+=+sin%282x%29%2F2


hopefully that is enough to help you finish the problem off. If not, then please let me know.

Also, I'm assuming the original equation should be (notice how I have cos%5E3%28b%29 and NOT cos%5E3%28a%29)