SOLUTION: Please help me to solve this word problem: Before the series of x rays are taken, a patient is injected with a special contrast mixture that highlights obstructions in his blood ve

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Question 923988: Please help me to solve this word problem: Before the series of x rays are taken, a patient is injected with a special contrast mixture that highlights obstructions in his blood vessels. The amount of the original dose of contrast material remaining in the patient's bloodstream h hours after it is injected is given by h -3/2. How much of the contrast material remains in the patient's bloodstream 4 hours after the injection?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
There is a typo.
Your formula does not make sense.
With h-3%2F2 , at h=0 (administration time), and h=1 hour,
you would have, respectively,
0-3%2F2=-3%2F2 and 1-3%2F2=-1%2F2 as a result.
Those are negative numbers, and that does not make sense.
What's worse, at h=2 hours, and at h=3 hours ,
the formula would tell you that the amount in the bloodstream would be
2-6%2F2=1%2F2 and 3-2%2F2=3%2F2 respectively.
It makes absolutely no sense to have negative levels in the blood at first, and then have the levels increase {linearly no less) with time.

The fraction of the original dose of contrast material remaining in the patient's bloodstream h hours after it is injected
must be something such as e%5E%28-%223%2F2%22h%29, or 2%5E%28-%223%2F2%22h%29 .
In general, that fraction of the initial dose should be B%5E%28-K%2Ah%29 with some positive constants B and K .
It has to be that what remains is a fraction of what was administered,
starting as 1 (the whole amount administered) at h=0 hours after administration,
and decreasing exponentially with time.
You need the right formula to know what fraction (something like 1/5 or 20%) remains in the bloodstream.
If they want an amount in milligram of drug, you also need the dose administered.