SOLUTION: what are the coordinates of the vertex of f(x)=-3x2+12x-9?

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Question 919447: what are the coordinates of the vertex of f(x)=-3x2+12x-9?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
the vertex form of a Parabola opening up(a>0) or down(a<0),
y=a%28x-h%29%5E2+%2Bk. V(h, k)
Completing the Square to Obtain the Vertex Form:
y = ax^2 + bx + c = 0
f(x)=-3x^2+12x-9 = 0 b%2F%28-2a%29+=+%2812%29%2F%286%29+=+2 2 the x-value for the Vertex
y = -3(x - 2)^2 + 12 -9 = 0 -a%28b%2F%28-2a%29%29%5E2+= 12
y = -3x - 2)^2 +3= 0
y = -3(x - 2)^2 + 3 = 0
V(2,3)