SOLUTION: Please please help me. Sketch the parabola 4x^2-8x+2 and label the vertex, axis of symmetry and x and y intercepts. SO far I think should divide the whole thing by 4 but I'm no

Algebra ->  Finance -> SOLUTION: Please please help me. Sketch the parabola 4x^2-8x+2 and label the vertex, axis of symmetry and x and y intercepts. SO far I think should divide the whole thing by 4 but I'm no      Log On


   

Question 897125: Please please help me.
Sketch the parabola 4x^2-8x+2 and label the vertex, axis of symmetry and x and y intercepts.
SO far I think should divide the whole thing by 4 but I'm not sure. Please help me.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Sketch the parabola 4x^2-8x+2 and label the vertex, axis of symmetry and x and y intercepts.
:
You can simplify it by dividing by 2 if you all you want are the x intercept and axis of symmetry, but if you want the y intercept and the vertex, you need the original equation.
:
the y intercept is easy, occurs when x = 0
y = 4(0^2) + 8(0) + 2
y = 2 is the y intercept
:
Plot this equation for x= -2 to x = +3
x | y
-------
-2 | 17
-1 | 14
0 | 2
+1 |-2
+2 |+2
+3 |+14
:
Should look like this
+graph%28+300%2C+200%2C+-4%2C+5%2C+-10%2C+20%2C+4x%5E2-8x%2B2%29+
Find the axis of symmetry using the formula x = -b/(2a)
x = %28-%28-8%29%29%2F%282%2A4%29
x = 8%2F8
x = 1 is the axis of symmetry as seen on the graph
:
The x intercepts are not integers, use the quadratic formula to find these
I got x = .293 and x = 1.71
:
Find the vertex, use the axis of symmetry, replace x with 1 in the equation
y = 4(1^2) - 8(1) + 2
y = 4 - 8 + 2
y = -2
The vertex is: 1, -2