SOLUTION: The general equation of a line through (4,0) which is parallel to the line containing points (1,0) and (3,-1) is

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Question 881676: The general equation of a line through (4,0) which is parallel to the line containing points (1,0) and (3,-1) is
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

(1,0) and 

(3,-1)  m = 1/-2 = -1/2

***Using point-slope form, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29P(4,0)

 y - 0 = (-1/2)(x - 4)

   y = (-1/2)x + 2

0r

    x + 2y = 4