SOLUTION: find three consecutive perfect square whose sum is 2030.

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Question 858033: find three consecutive perfect square whose sum is 2030.
Found 2 solutions by Seutip, Alan3354:
Answer by Seutip(231) About Me  (Show Source):
You can put this solution on YOUR website!
Let:
x%5E2, %28x%2B1%29%5E2 and %28x%2B2%29%5E2 be the three consecutive perfect square.
x%5E2%2B%28x%2B1%29%5E2%2B%28x%2B2%29%5E2=2030
x%5E2%2B%28x%5E2%2B2x%2B1%29%2B%28x%5E2%2B4x%2B4%29=2030
3x%5E2%2B6x%2B5=2030
3x%5E2%2B6x=2025
x%5E2%2B2x=675
x%5E2%2B2x-675=0
%28x%2B27%29%28x-25%29=0
x%2B27=0
x=-27
x-25=0
x=25

So the perfect squares are...
25^2 = 625
25+1^2 = 676
25+2^2 = 729
Which all in all totals to 2030!


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Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find three consecutive perfect square whose sum is 2030.
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2030/3 = ~676, which is 26^2
--> 25^2 + 26^2 + 27^2
or (-25)^2 + (-26)^2 + (-27)^2
625 + 676 + 729